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\(magnetic field intensity, H=NI/l\) A solenoid has 500 turns of wire and a length of 0.4 meters. If a current of 2 A flows through the solenoid, calculate

\(magnetic field intensity,
H=NI/l\)

A solenoid has 500 turns of wire and a length of 0.4 meters. If a current of 2 A flows through the solenoid, calculate the magnetic field strength inside the solenoid.

Hint: Use the formula for the magnetic field inside a solenoid:

H=NILH = \frac{NI}{L}H=LNI​

Where:

  • HHH is the magnetic field strength (in A/m),
  • NNN is the number of turns,
  • III is the current (in amperes),
  • LLL is the length of the solenoid (in meters).

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